What is expand (8-2x)(7x+3)(x) ?

The solution to expand (8-2x)(7x+3)(x) is 7x^2(8-2x)+3x(8-2x)

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expand (8-2x)(7x+3)(x)

expand

(8 - 2 x)^{\circ} (7 x + 3) (x)

7 x^{2} (8 - 2 x)^{\circ} + 3 x (8 - 2 x)^{\circ}

Solution steps

(8 - 2 x)^{\circ} (7 x + 3) (x)

= (x) (7 x + 3) (8 - 2 x)^{\circ}

Apply the distributive law:

a (b + c) = ab + a c

a = (8 - 2 x)^{\circ} (x), b = 7 x, c = 3

= (8 - 2 x)^{\circ} (x) \cdot 7 x + (8 - 2 x)^{\circ} (x) \cdot 3

= 7 (x) x (8 - 2 x)^{\circ} + 3 (x) (8 - 2 x)^{\circ}

Simplify

7 (x) x (8 - 2 x)^{\circ} + 3 (x) (8 - 2 x)^{\circ} : 7 x^{2} (8 - 2 x)^{\circ} + 3 x (8 - 2 x)^{\circ}

= 7 x^{2} (8 - 2 x)^{\circ} + 3 x (8 - 2 x)^{\circ}

- (\frac{z ( z + 2 )}{( z ^{2} + z + 1 ) ^{2}})

\frac{( - x + 2 + ( x + 1 ) x - 2 )}{( x + 1 )}

\frac{x + 4}{( x - 2 ) ( x - 4 )}

4 (1 + sin^{2} (3 x))^{3}

What is expand (8-2x)(7x+3)(x) ?
The solution to expand (8-2x)(7x+3)(x) is 7x^2(8-2x)+3x(8-2x)