What is expand e^x(x^2-2(x-1)) ?

The solution to expand e^x(x^2-2(x-1)) is e^xx^2-2e^xx+2e^x

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expand e^x(x^2-2(x-1))

expand

e^{x} (x^{2} - 2 (x - 1))

e^{x} x^{2} - 2 e^{x} x + 2 e^{x}

Solution steps

e^{x} (x^{2} - 2 (x - 1))

Apply the distributive law:

a (b - c) = ab - a c

a = e^{x}, b = x^{2}, c = 2 (x - 1)

= e^{x} x^{2} - e^{x} \cdot 2 (x - 1)

= e^{x} x^{2} - 2 e^{x} (x - 1)

Expand

- 2 e^{x} (x - 1) : - 2 e^{x} x + 2 e^{x}

= e^{x} x^{2} - 2 e^{x} x + 2 e^{x}

(x + 3 x) (x - 2 x)

lo g_{5} (125)

\frac{10}{( s + 1 ) ^{2} ( s + 3 )}

- 5 (4 x + y = 1)

\frac{( t ^{2} - 2 t ) ( t + 1 ) ^{2}}{- t ^{2} - 1}

What is expand e^x(x^2-2(x-1)) ?
The solution to expand e^x(x^2-2(x-1)) is e^xx^2-2e^xx+2e^x