What is (1/(x^6y)-1/7)(x^{4/9}y^{1/3}) ?

The solution to (1/(x^6y)-1/7)(x^{4/9}y^{1/3}) is (7-x^6y)/(7x^{50/9)y^{2/3}}

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simplify (1/(x^6y)-1/7)(x^{4/9}y^{1/3})

simplify

(\frac{1}{x ^{6} y} - \frac{1}{7}) (x^{\frac{4}{9}} y^{\frac{1}{3}})

\frac{7 - x ^{6} y}{7 x ^{\frac{50}{9}} y ^{\frac{2}{3}}}

Solution steps

(\frac{1}{x ^{6} y} - \frac{1}{7}) (x^{\frac{4}{9}} y^{\frac{1}{3}})

Join

\frac{1}{x ^{6} y} - \frac{1}{7} : \frac{7 - x ^{6} y}{7 x ^{6} y}

= \frac{7 - x ^{6} y}{7 x ^{6} y} x^{\frac{4}{9}} y^{\frac{1}{3}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 7 - x ^{6} y ) x ^{\frac{4}{9}} y ^{\frac{1}{3}}}{7 x ^{6} y}

Simplify

\frac{x ^{\frac{4}{9}}}{x ^{6}} : \frac{1}{x ^{\frac{50}{9}}}

= \frac{( 7 - x ^{6} y ) y ^{\frac{1}{3}}}{7 x ^{\frac{50}{9}} y}

Simplify

\frac{y ^{\frac{1}{3}}}{y} : \frac{1}{y ^{\frac{2}{3}}}

= \frac{7 - x ^{6} y}{7 x ^{\frac{50}{9}} y ^{\frac{2}{3}}}

(2 x^{2} + \frac{a}{x ^{3}})^{10}

sec ((7 x^{5} + 6 x + 7)^{2}) (35 x^{4} + 6)

2 (1 - x) (13.4784, 26)

0.025 (0.1 e^{- 4 t} - 0.4 t e^{- 4 t})^{2}

\frac{A}{( x - 1 ) ^{2}} + \frac{B}{x - 1} + \frac{C}{x - 0.3679}

What is (1/(x^6y)-1/7)(x^{4/9}y^{1/3}) ?
The solution to (1/(x^6y)-1/7)(x^{4/9}y^{1/3}) is (7-x^6y)/(7x^{50/9)y^{2/3}}