What is ((-1)^nx^n+5^nx^{2k})/(2^k) ?

The solution to ((-1)^nx^n+5^nx^{2k})/(2^k) is ((-x)^n+5^nx^{2k})/(2^k)

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simplify ((-1)^nx^n+5^nx^{2k})/(2^k)

simplify

\frac{( - 1 ) ^{n} x ^{n} + 5 ^{n} x ^{2 k}}{2 ^{k}}

\frac{( - x ) ^{n} + 5 ^{n} x ^{2 k}}{2 ^{k}}

Solution steps

\frac{( - 1 ) ^{n} x ^{n} + 5 ^{n} x ^{2 k}}{2 ^{k}}

Apply exponent rule:

a^{n} b^{n} = (a \cdot b)^{n}

(- 1)^{n} x^{n} = (- 1 \cdot x)^{n}

= \frac{( - 1 \cdot x ) ^{n} + 5 ^{n} x ^{2 k}}{2 ^{k}}

Apply rule:

1 \cdot a = a

- 1 \cdot x = - x

= \frac{( - x ) ^{n} + 5 ^{n} x ^{2 k}}{2 ^{k}}

\frac{17 x - 16}{( x - 1 ) ^{2}}

(t^{2} + 2 t) \cdot cos (4 t)

\frac{( 0.77 W + ( 0.61 W + 612 ) ^{2.04} )}{W}

sin (5 (t - w)) y (w)

\frac{7 x ^{2}}{( x - 4 ) ^{2} ( x + 4 ) ^{2}}

What is ((-1)^nx^n+5^nx^{2k})/(2^k) ?
The solution to ((-1)^nx^n+5^nx^{2k})/(2^k) is ((-x)^n+5^nx^{2k})/(2^k)