What is expand (n^2+3n)/(2(n+1)(n+2)) ?

The solution to expand (n^2+3n)/(2(n+1)(n+2)) is (n^2+3n)/(2n^2+6n+4)

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expand (n^2+3n)/(2(n+1)(n+2))

expand

\frac{n ^{2} + 3 n}{2 ( n + 1 ) ( n + 2 )}

\frac{n ^{2} + 3 n}{2 n ^{2} + 6 n + 4}

Solution steps

\frac{n ^{2} + 3 n}{2 ( n + 1 ) ( n + 2 )}

Expand

2 (n + 1) (n + 2) : 2 n^{2} + 6 n + 4

= \frac{n ^{2} + 3 n}{2 n ^{2} + 6 n + 4}

\frac{4 ( 3 x + 6 )}{5}

\frac{1}{2 ( x ^{2} + 1 )}

(x + 2 i) (x - 2 i)

(e^{(2 t)} + 5) \cdot sin (3 t)

8 (\frac{3 π}{2} - 1)

What is expand (n^2+3n)/(2(n+1)(n+2)) ?
The solution to expand (n^2+3n)/(2(n+1)(n+2)) is (n^2+3n)/(2n^2+6n+4)