What is expand-4(x+2)(-1/4 = x/(-4(x+2))) ?

The solution to expand-4(x+2)(-1/4 = x/(-4(x+2))) is -4x(-1/4 = x/(-4(x+2)))-4*2(-1/4 = x/(-4(x+2)))

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expand-4(x+2)(-1/4 = x/(-4(x+2)))

expand

- 4 (x + 2) (- \frac{1}{4} = \frac{x}{- 4 ( x + 2 )})

- 4 x (- \frac{1}{4} = \frac{x}{- 4 ( x + 2 )}) - 4 \cdot 2 (- \frac{1}{4} = \frac{x}{- 4 ( x + 2 )})

Solution steps

- 4 (x + 2) (- \frac{1}{4} = \frac{x}{- 4 ( x + 2 )})

Apply the distributive law:

a (b + c) = ab + a c

a = - 4 (- \frac{1}{4} = \frac{x}{- 4 ( x + 2 )}), b = x, c = 2

= - 4 (- \frac{1}{4} = \frac{x}{- 4 ( x + 2 )}) x + (- 4 (- \frac{1}{4} = \frac{x}{- 4 ( x + 2 )})) \cdot 2

Apply minus-plus rules

+ (- a) = - a

= - 4 x (- \frac{1}{4} = \frac{x}{- 4 ( x + 2 )}) - 4 \cdot 2 (- \frac{1}{4} = \frac{x}{- 4 ( x + 2 )})

\frac{x ( x + 3 )}{x ^{2} + x - 12}

(\frac{2}{x + 2} + x) \cdot x

y \cdot lo g_{10} (x) + (1 - y) \cdot lo g_{10} (1 - x + z)

\frac{( 5 s ^{3} - 56 s ^{2} + 46 s - 534 )}{( s ^{2} + 9 ) ( s - 6 ) ^{2}}

\frac{1}{x ^{3} ( s - 1 ) ( s - 2 )}

What is expand-4(x+2)(-1/4 = x/(-4(x+2))) ?
The solution to expand-4(x+2)(-1/4 = x/(-4(x+2))) is -4x(-1/4 = x/(-4(x+2)))-4*2(-1/4 = x/(-4(x+2)))