What is expand (-2,-3)(3x+5y-12=0) ?

The solution to expand (-2,-3)(3x+5y-12=0) is -2,3x-2,5y+2,12=0-3*3x-3*5y+3*12=0

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expand (-2,-3)(3x+5y-12=0)

expand

(- 2, - 3) (3 x + 5 y - 12 = 0)

- 2, 3 x - 2, 5 y + 2, 12 = 0 - 3 \cdot 3 x - 3 \cdot 5 y + 3 \cdot 12 = 0

Solution steps

(- 2, - 3) (3 x + 5 y - 12 = 0)

= (- 2, - 3) (3 x + 5 y - 12 \cdot 0 =)

Distribute parentheses

= (- 2,) \cdot 3 x + (- 2,) \cdot 5 y + (- 2,) (- 12 = 0) + (- 3) \cdot 3 x + (- 3) \cdot 5 y + (- 3) (- 12 = 0)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

- 2, 3 x - 2, 5 y + 2, 12 = 0 - 3 \cdot 3 x - 3 \cdot 5 y + 3 \cdot 12 = 0

- csc (x) (sin (4 x) - 2 sin (3 x) cos (x))

\frac{12 x ^{3}}{3 x}

2 (e^{5} - 1)

25 (- 46 + 4)

\frac{( 7 x - 2 ) ^{n}}{( n + 3 ) ^{2}}

What is expand (-2,-3)(3x+5y-12=0) ?
The solution to expand (-2,-3)(3x+5y-12=0) is -2,3x-2,5y+2,12=0-3*3x-3*5y+3*12=0