What is (x+1/4)(x^2-5x) ?

The solution to (x+1/4)(x^2-5x) is ((4x+1)(x^2-5x))/4

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simplify (x+1/4)(x^2-5x)

simplify

(x + \frac{1}{4}) (x^{2} - 5 x)

\frac{( 4 x + 1 ) ( x ^{2} - 5 x )}{4}

Solution steps

(x + \frac{1}{4}) (x^{2} - 5 x)

Simplify

x + \frac{1}{4} : \frac{4 x + 1}{4}

= \frac{4 x + 1}{4} (x^{2} - 5 x)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 4 x + 1 ) ( x ^{2} - 5 x )}{4}

(- (a) + a^{2} - 4 c)^{2}

[(t) cos (4 t) U (t - (\frac{π}{4}))]

\frac{1}{( 1 - 3 x ) ^{3}}

3 (3 x^{2} + 2 x - 6)^{2}

(q + r^{2} - y^{2})^{2}