What is expand (x-3)(x+0.5)(x-1/3) ?

The solution to expand (x-3)(x+0.5)(x-1/3) is x^3-(2x)/3-(17x^2)/6+1/2

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expand (x-3)(x+0.5)(x-1/3)

expand

(x - 3) (x + 0.5) (x - \frac{1}{3})

x^{3} - \frac{2 x}{3} - \frac{17 x ^{2}}{6} + \frac{1}{2}

Solution steps

(x - 3) (x + 0.5) (x - \frac{1}{3})

Expand

(x - 3) (x + 0.5) (x - \frac{1}{3}) : (x^{2} - 2.5 x - 1.5) (x - \frac{1}{3})

= (x^{2} - 2.5 x - 1.5) (x - \frac{1}{3})

Distribute parentheses

= x^{2} x + x^{2} (- \frac{1}{3}) - 2.5 xx - 2.5 x (- \frac{1}{3}) - 1.5 x - 1.5 (- \frac{1}{3})

Simplify

x^{2} x + x^{2} (- \frac{1}{3}) - 2.5 xx - 2.5 x (- \frac{1}{3}) - 1.5 x - 1.5 (- \frac{1}{3}) : x^{3} - \frac{2 x}{3} - \frac{17 x ^{2}}{6} + \frac{1}{2}

= x^{3} - \frac{2 x}{3} - \frac{17 x ^{2}}{6} + \frac{1}{2}

- \frac{1}{( 3 ) ( 1 - ln ( 3 ) )}

10 (2157 - 25)

\frac{3 x ^{3} + 6 x ^{2} + 3 x + 4}{x ^{2} ( x ^{2} + 1 )}

(x^{4} + 2 x^{2} + 2) l e f t (x^{2} - 2 x + 3)

\frac{1}{( 1 - 3 x ) ^{4}}

What is expand (x-3)(x+0.5)(x-1/3) ?
The solution to expand (x-3)(x+0.5)(x-1/3) is x^3-(2x)/3-(17x^2)/6+1/2