What is (1/2-z^2)(1/2+z) ?

The solution to (1/2-z^2)(1/2+z) is ((-2z^2+1)(2z+1))/4

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simplify (1/2-z^2)(1/2+z)

simplify

(\frac{1}{2} - z^{2}) (\frac{1}{2} + z)

\frac{( - 2 z ^{2} + 1 ) ( 2 z + 1 )}{4}

Solution steps

(\frac{1}{2} - z^{2}) (\frac{1}{2} + z)

Simplify

\frac{1}{2} - z^{2} : \frac{- 2 z ^{2} + 1}{2}

= \frac{- 2 z ^{2} + 1}{2} (\frac{1}{2} + z)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 2 z ^{2} + 1 ) ( \frac{1}{2} + z )}{2}

Simplify

(- 2 z^{2} + 1) (\frac{1}{2} + z) : \frac{( - 2 z ^{2} + 1 ) ( z \cdot 2 + 1 )}{2}

= \frac{\frac{( - 2 z ^{2} + 1 ) ( z \cdot 2 + 1 )}{2}}{2}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( - 2 z ^{2} + 1 ) ( z \cdot 2 + 1 )}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{( - 2 z ^{2} + 1 ) ( z \cdot 2 + 1 )}{4}

= \frac{( - 2 z ^{2} + 1 ) ( 2 z + 1 )}{4}

(ln (3) - 2) \times 6

m u lt i pl y (x + 12) (x - 0) (x - 20)

(4, - 5) Y^{3}

(2 x^{3} - \frac{5}{x}) 30

\frac{4 x ^{3} + 2 x ^{2}}{2 x ^{2}}

What is (1/2-z^2)(1/2+z) ?
The solution to (1/2-z^2)(1/2+z) is ((-2z^2+1)(2z+1))/4