What is expand ((x-2)(x+2))/((x-4)^2) ?

The solution to expand ((x-2)(x+2))/((x-4)^2) is (x^2-4)/(x^2-8x+16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x-2)(x+2))/((x-4)^2)

expand

\frac{( x - 2 ) ( x + 2 )}{( x - 4 ) ^{2}}

\frac{x ^{2} - 4}{x ^{2} - 8 x + 16}

Solution steps

\frac{( x - 2 ) ( x + 2 )}{( x - 4 ) ^{2}}

(x - 4)^{2} = x^{2} - 8 x + 16

= \frac{( x - 2 ) ( x + 2 )}{x ^{2} - 8 x + 16}

Expand

(x - 2) (x + 2) : x^{2} - 4

= \frac{x ^{2} - 4}{x ^{2} - 8 x + 16}

(\frac{1}{3} - x) (1 - x)

(i + k + j) (i + ik + kj + j)^{2}

x^{3} - 8 + x - 2

(10 - 4 cos (θ))^{2}

so l v e (x + 5) (x - 1)

What is expand ((x-2)(x+2))/((x-4)^2) ?
The solution to expand ((x-2)(x+2))/((x-4)^2) is (x^2-4)/(x^2-8x+16)