What is expand-(2x+1)sin(x^2+x) ?

The solution to expand-(2x+1)sin(x^2+x) is -2xsin(x^2+x)-sin(x^2+x)

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expand-(2x+1)sin(x^2+x)

expand

- (2 x + 1) sin (x^{2} + x)

- 2 x sin (x^{2} + x) - sin (x^{2} + x)

Solution steps

- (2 x + 1) sin (x^{2} + x)

= - sin (x^{2} + x) (2 x + 1)

Apply the distributive law:

a (b + c) = ab + a c

- sin (x^{2} + x) (2 x + 1) = - sin (x^{2} + x) \cdot 2 x - sin (x^{2} + x) \cdot 1

= - sin (x^{2} + x) \cdot 2 x - sin (x^{2} + x) \cdot 1

Simplify

- sin (x^{2} + x) \cdot 2 x - sin (x^{2} + x) \cdot 1 : - 2 x sin (x^{2} + x) - sin (x^{2} + x)

= - 2 x sin (x^{2} + x) - sin (x^{2} + x)

4 (4 x + \frac{1}{x})

\frac{2 ( x - 8 )}{( x - 5 ) ^{2}}

\frac{5 ( 6 - x ) ^{2}}{3}

R (- 3, 2, - 5) S (- 5, 1, - 3)

\frac{d ^{3}}{d x ^{3}} ((y) (4 x^{5} - 3 x^{4} + 2 x))

What is expand-(2x+1)sin(x^2+x) ?
The solution to expand-(2x+1)sin(x^2+x) is -2xsin(x^2+x)-sin(x^2+x)