What is expand ((3x^2+3sqrt(x))x^4-6)/(2x^4) ?

The solution to expand ((3x^2+3sqrt(x))x^4-6)/(2x^4) is (3x^2)/2+(3sqrt(x))/2-3/(x^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((3x^2+3sqrt(x))x^4-6)/(2x^4)

expand

\frac{( 3 x ^{2} + 3 x ) x ^{4} - 6}{2 x ^{4}}

\frac{3 x ^{2}}{2} + \frac{3 x}{2} - \frac{3}{x ^{4}}

Solution steps

\frac{( 3 x ^{2} + 3 x ) x ^{4} - 6}{2 x ^{4}}

Expand

(3 x^{2} + 3 x) x^{4} - 6 : 3 x^{6} + 3 x^{4} x - 6

= \frac{3 x ^{6} + 3 x ^{4} x - 6}{2 x ^{4}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{6} + 3 x ^{4} x - 6}{2 x ^{4}} = \frac{3 x ^{6}}{2 x ^{4}} + \frac{3 x ^{4} x}{2 x ^{4}} - \frac{6}{2 x ^{4}}

= \frac{3 x ^{6}}{2 x ^{4}} + \frac{3 x ^{4} x}{2 x ^{4}} - \frac{6}{2 x ^{4}}

Cancel

\frac{3 x ^{6}}{2 x ^{4}} : \frac{3 x ^{2}}{2}

= \frac{3 x ^{2}}{2} + \frac{3 x ^{4} x}{2 x ^{4}} - \frac{6}{2 x ^{4}}

Cancel

\frac{3 x ^{4} x}{2 x ^{4}} : \frac{3 x}{2}

= \frac{3 x ^{2}}{2} + \frac{3 x}{2} - \frac{6}{2 x ^{4}}

Divide the numbers:

\frac{6}{2} = 3

= \frac{3 x ^{2}}{2} + \frac{3 x}{2} - \frac{3}{x ^{4}}

f^{'} (x) ((- 6 + 9 x) (- 9 - 9 x^{2} - 6 x^{3}))

\frac{( 2 x ^{2} + 9 ) ( x ^{2} + 2 )}{x ^{2}}

\frac{8 e ^{- s} - 1}{4 ( 2 - 3 s + s ^{2} )}

\frac{\partial}{\partial y} ((x) (2 x + y cos (x y)))

f (p - \frac{1}{4})

What is expand ((3x^2+3sqrt(x))x^4-6)/(2x^4) ?
The solution to expand ((3x^2+3sqrt(x))x^4-6)/(2x^4) is (3x^2)/2+(3sqrt(x))/2-3/(x^4)