What is expand (-s^2+5s-3)/((s-4)(s^2+2s-3)) ?

The solution to expand (-s^2+5s-3)/((s-4)(s^2+2s-3)) is (-s^2+5s-3)/(s^3-2s^2-11s+12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (-s^2+5s-3)/((s-4)(s^2+2s-3))

expand

\frac{- s ^{2} + 5 s - 3}{( s - 4 ) ( s ^{2} + 2 s - 3 )}

\frac{- s ^{2} + 5 s - 3}{s ^{3} - 2 s ^{2} - 11 s + 12}

Solution steps

\frac{- s ^{2} + 5 s - 3}{( s - 4 ) ( s ^{2} + 2 s - 3 )}

Expand

(s - 4) (s^{2} + 2 s - 3) : s^{3} - 2 s^{2} - 11 s + 12

= \frac{- s ^{2} + 5 s - 3}{s ^{3} - 2 s ^{2} - 11 s + 12}

(x^{3} + 2)^{7}

7 (9 x_{- 4})

\frac{12 ( 2 - e ^{\frac{π}{12}} )}{π e ^{\frac{π}{4}}}

\frac{\frac{1}{a + h} - \frac{1}{a}}{h}

ln (3) (x + 2)

What is expand (-s^2+5s-3)/((s-4)(s^2+2s-3)) ?
The solution to expand (-s^2+5s-3)/((s-4)(s^2+2s-3)) is (-s^2+5s-3)/(s^3-2s^2-11s+12)