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Popular >

expand ρ(y_{t-1}=βx_{t-1}+u_{t-1}(ρ,y,t,x))

Solution

expand

ρ (y_{t - 1} = β x_{t - 1} + u_{t - 1} (ρ, y, t, x))

Solution

ρ y_{t - 1} = β x_{t - 1} + ρ u_{t - 1} (,,, ρ y t x)

Solution steps

ρ (y_{t - 1} = β x_{t - 1} + u_{t - 1} (ρ, y, t, x))

= ρ (= β y_{t - 1} x_{t - 1} + u_{t - 1} (,,, ρ y t x))

Apply the distributive law:

a (b + c) = ab + a c

a = ρ, b = y_{t - 1} = β x_{t - 1}, c = u_{t - 1} (ρ, y, t, x)

ρ y_{t - 1} = β x_{t - 1} + ρ u_{t - 1} (ρ, y, t, x)

ρ y_{t - 1} = β x_{t - 1} + ρ u_{t - 1} (,,, ρ y t x)

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Frequently Asked Questions (FAQ)

What is expand ρ(y_{t-1}=βx_{t-1}+u_{t-1}(ρ,y,t,x)) ?
The solution to expand ρ(y_{t-1}=βx_{t-1}+u_{t-1}(ρ,y,t,x)) is ρy_{t-1}=βx_{t-1}+ρu_{t-1}(,,,ρytx)