What is expand ((5y-3)/2)^2 ?

The solution to expand ((5y-3)/2)^2 is (25y^2)/4-(15y)/2+9/4

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expand ((5y-3)/2)^2

expand

(\frac{5 y - 3}{2})^{2}

\frac{25 y ^{2}}{4} - \frac{15 y}{2} + \frac{9}{4}

Solution steps

(\frac{5 y - 3}{2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 5 y - 3 ) ^{2}}{2 ^{2}}

(5 y - 3)^{2} = 25 y^{2} - 30 y + 9

= \frac{25 y ^{2} - 30 y + 9}{2 ^{2}}

2^{2} = 4

= \frac{25 y ^{2} - 30 y + 9}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{25 y ^{2} - 30 y + 9}{4} = \frac{25 y ^{2}}{4} - \frac{30 y}{4} + \frac{9}{4}

= \frac{25 y ^{2}}{4} - \frac{30 y}{4} + \frac{9}{4}

Cancel

\frac{30 y}{4} : \frac{15 y}{2}

= \frac{25 y ^{2}}{4} - \frac{15 y}{2} + \frac{9}{4}

sin^{2} (x) (cot (x) - csc (x))

\frac{13}{2} (e^{3 t} - e^{- 3 t})

(sec (x) + tan (x)) co x - 1

(\frac{5 ^{- 3}}{5 ^{- 5}})^{2}

(1, 6) y (5, - 2)

What is expand ((5y-3)/2)^2 ?
The solution to expand ((5y-3)/2)^2 is (25y^2)/4-(15y)/2+9/4