What is expand dx(1/15 arcsec(x/5)+c) ?

The solution to expand dx(1/15 arcsec(x/5)+c) is (arcsec(x/5)dx)/(15)+cdx

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expand dx(1/15 arcsec(x/5)+c)

expand

d x (\frac{1}{15} arcsec (\frac{x}{5}) + c)

\frac{arcsec ( \frac{x}{5} ) d x}{15} + c d x

Solution steps

d x (\frac{1}{15} arcsec (\frac{x}{5}) + c)

Apply the distributive law:

a (b + c) = ab + a c

a = d x, b = \frac{1}{15} arcsec (\frac{x}{5}), c = c

= d x \frac{1}{15} arcsec (\frac{x}{5}) + d x c

= \frac{1}{15} arcsec (\frac{x}{5}) d x + c d x

Simplify

\frac{1}{15} arcsec (\frac{x}{5}) d x + c d x : \frac{arcsec ( \frac{x}{5} ) d x}{15} + c d x

= \frac{arcsec ( \frac{x}{5} ) d x}{15} + c d x

(x - \frac{a}{x ^{2}})^{9}

3 (\frac{x}{2} - 1)

(csc (2 x) - 1) sin (x)

3 (\frac{x}{2} - 4)

\frac{1}{2} (sin (x - y) + sin (x + y))

What is expand dx(1/15 arcsec(x/5)+c) ?
The solution to expand dx(1/15 arcsec(x/5)+c) is (arcsec(x/5)dx)/(15)+cdx