What is the d/(dp)((h)(60h^5+2-p^3)) ?

The d/(dp)((h)(60h^5+2-p^3)) is -3hp^2

What is the first d/(dp)((h)(60h^5+2-p^3)) ?

The first d/(dp)((h)(60h^5+2-p^3)) is -3hp^2

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\frac{d}{d p} ((h) (60 h^{5} + 2 - p^{3}))

- 3 h p^{2}

Solution steps

\frac{d}{d p} ((h) (60 h^{5} + 2 - p^{3}))

Treat

h

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= h \frac{d}{d p} (60 h^{5} + 2 - p^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= h (\frac{d}{d p} (60 h^{5}) + \frac{d}{d p} (2) - \frac{d}{d p} (p^{3}))

\frac{d}{d p} (60 h^{5}) = 0

\frac{d}{d p} (2) = 0

\frac{d}{d p} (p^{3}) = 3 p^{2}

= h (0 + 0 - 3 p^{2})

Simplify

= - 3 h p^{2}

\frac{d ^{2}}{d x ^{2}} ((y) (5 x^{2} - 3) (7 x^{3} + x))

(x - 4 + 1)^{2}

\frac{4 ( 20 10 - 2 )}{27}

\frac{8 ( 12 - 24 c )}{35}

\frac{d}{d y} ((x (y)) (y^{4} + 4))

What is the d/(dp)((h)(60h^5+2-p^3)) ?
The d/(dp)((h)(60h^5+2-p^3)) is -3hp^2
What is the first d/(dp)((h)(60h^5+2-p^3)) ?
The first d/(dp)((h)(60h^5+2-p^3)) is -3hp^2