What is (x/3-2)(x/3-3) ?

The solution to (x/3-2)(x/3-3) is ((-6+x)(-9+x))/9

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simplify (x/3-2)(x/3-3)

simplify

(\frac{x}{3} - 2) (\frac{x}{3} - 3)

\frac{( - 6 + x ) ( - 9 + x )}{9}

Solution steps

(\frac{x}{3} - 2) (\frac{x}{3} - 3)

Join

\frac{x}{3} - 2 : \frac{- 6 + x}{3}

= \frac{- 6 + x}{3} (\frac{x}{3} - 3)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 6 + x ) ( \frac{x}{3} - 3 )}{3}

Simplify

(- 6 + x) (\frac{x}{3} - 3) : \frac{( - 6 + x ) ( - 9 + x )}{3}

= \frac{\frac{( - 6 + x ) ( - 9 + x )}{3}}{3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( - 6 + x ) ( - 9 + x )}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{( - 6 + x ) ( - 9 + x )}{9}

(x + 3) (x - 3) (x - 2)

7 (\frac{3}{5} u - \frac{3}{23} v)^{2}

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\frac{z ^{2} + 7 z + 11}{( z ^{2} + 7 z + 1 ) ( z ^{2} + 7 z + 12 )}

(x^{2} - 2 y^{2}) e^{x - y}