What is expand (uIθ(a-b))/(4pi) ?

The solution to expand (uIθ(a-b))/(4pi) is (auIθ)/(4pi)-(buIθ)/(4pi)

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expand (uIθ(a-b))/(4pi)

expand

\frac{u I θ ( a - b )}{4 π}

\frac{a u I θ}{4 π} - \frac{b u I θ}{4 π}

Solution steps

\frac{u I θ ( a - b )}{4 π}

Expand

u I θ (a - b) : a u I θ - b u I θ

= \frac{a u I θ - b u I θ}{4 π}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{a u I θ - b u I θ}{4 π} = \frac{a u I θ}{4 π} - \frac{b u I θ}{4 π}

= \frac{a u I θ}{4 π} - \frac{b u I θ}{4 π}

\frac{2 sin ( θ ) ( sin ( θ ) + 1 )}{1 + sin ( θ ) + cos ( θ )}

\frac{3 ( 12 n ^{2} + 15 n + 3 )}{2 n ^{2}}

\frac{- 22 s - 8}{( s + 4 ) ( s ^{2} + 4 )}

2 (x + 3 - (1 + x) 5 + 4 x - 1 + x)

(2 x^{3} + 6 x + 1)^{2}

What is expand (uIθ(a-b))/(4pi) ?
The solution to expand (uIθ(a-b))/(4pi) is (auIθ)/(4pi)-(buIθ)/(4pi)