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The solutions to the quadratic equation are:
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What are the solutions to the equation 2x^2=(x+3)^2 ?
The solutions to the equation 2x^2=(x+3)^2 are x=-3(sqrt(2)-1),x=3(1+sqrt(2))Find the zeros of 2x^2=(x+3)^2
The zeros of 2x^2=(x+3)^2 are x=-3(sqrt(2)-1),x=3(1+sqrt(2))