What is (x-5/3)*(x-7/3) ?

The solution to (x-5/3)*(x-7/3) is ((3x-5)(3x-7))/9

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simplify (x-5/3)*(x-7/3)

simplify

(x - \frac{5}{3}) \cdot (x - \frac{7}{3})

\frac{( 3 x - 5 ) ( 3 x - 7 )}{9}

Solution steps

(x - \frac{5}{3}) (x - \frac{7}{3})

Simplify

x - \frac{5}{3} : \frac{3 x - 5}{3}

= \frac{3 x - 5}{3} (x - \frac{7}{3})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 3 x - 5 ) ( x - \frac{7}{3} )}{3}

Simplify

(3 x - 5) (x - \frac{7}{3}) : \frac{( 3 x - 5 ) ( x \cdot 3 - 7 )}{3}

= \frac{\frac{( 3 x - 5 ) ( x \cdot 3 - 7 )}{3}}{3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 3 x - 5 ) ( x \cdot 3 - 7 )}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{( 3 x - 5 ) ( x \cdot 3 - 7 )}{9}

= \frac{( 3 x - 5 ) ( 3 x - 7 )}{9}

(- v sin^{2} (u) - v cos^{2} (u))^{2}

(t + 2 t)^{4}

3 y^{2} (6 - 3 y) - \frac{1}{6} y (6 - 3 y)^{3} - \frac{3}{2} y^{3} (6 - 3 y)

\frac{x ^{2} + 2 x + 3}{( x - 1 ) ^{2} ( x ^{2} + 1 )}

343 \cdot 63