What is expand-(4(72-5P^2))/3 ?

The solution to expand-(4(72-5P^2))/3 is (20P^2)/3-96

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expand-(4(72-5P^2))/3

expand

- \frac{4 ( 72 - 5 P ^{2} )}{3}

\frac{20 P ^{2}}{3} - 96

Solution steps

- \frac{4 ( 72 - 5 P ^{2} )}{3}

Expand

4 (72 - 5 P^{2}) : 288 - 20 P^{2}

= - \frac{- 20 P ^{2} + 288}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{288 - 20 P ^{2}}{3} = - (\frac{288}{3}) - (- \frac{20 P ^{2}}{3})

= - (\frac{288}{3}) - (- \frac{20 P ^{2}}{3})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{288}{3} + \frac{20 P ^{2}}{3}

Divide the numbers:

\frac{288}{3} = 96

= - 96 + \frac{20 P ^{2}}{3}

Rewrite in standard form

= \frac{20 P ^{2}}{3} - 96

\frac{k ( s + 2 ) ( s + 1 )}{( s - 2 ) ( s - 1 )}

6 (x + 5)

(cos (x) - 1) (2 sin (x) + 1)

(\frac{7}{x - 12} + 6 (100 - x)) (x - 12)

\frac{5}{7} \cdot (1 + ln (\frac{7}{5}))

What is expand-(4(72-5P^2))/3 ?
The solution to expand-(4(72-5P^2))/3 is (20P^2)/3-96