What is expand-1/324 (6-2z)^4 ?

The solution to expand-1/324 (6-2z)^4 is -4+(16z)/3-(8z^2)/3+(16z^3)/(27)-(4z^4)/(81)

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expand-1/324 (6-2z)^4

expand

- \frac{1}{324} (6 - 2 z)^{4}

- 4 + \frac{16 z}{3} - \frac{8 z ^{2}}{3} + \frac{16 z ^{3}}{27} - \frac{4 z ^{4}}{81}

Solution steps

- \frac{1}{324} (6 - 2 z)^{4}

Expand

(6 - 2 z)^{4} : 1296 - 1728 z + 864 z^{2} - 192 z^{3} + 16 z^{4}

= - \frac{1}{324} (1296 - 1728 z + 864 z^{2} - 192 z^{3} + 16 z^{4})

Distribute parentheses

= - \frac{1}{324} \cdot 1296 - \frac{1}{324} (- 1728 z) - \frac{1}{324} \cdot 864 z^{2} - \frac{1}{324} (- 192 z^{3}) - \frac{1}{324} \cdot 16 z^{4}

Simplify

- \frac{1}{324} \cdot 1296 - \frac{1}{324} (- 1728 z) - \frac{1}{324} \cdot 864 z^{2} - \frac{1}{324} (- 192 z^{3}) - \frac{1}{324} \cdot 16 z^{4} : - 4 + \frac{16 z}{3} - \frac{8 z ^{2}}{3} + \frac{16 z ^{3}}{27} - \frac{4 z ^{4}}{81}

= - 4 + \frac{16 z}{3} - \frac{8 z ^{2}}{3} + \frac{16 z ^{3}}{27} - \frac{4 z ^{4}}{81}

(- a sin (t) - a sin (2 t))^{2} + (a cos (t) + a cos (2 t))^{2}

\frac{\partial}{\partial x} ((y) (3 x^{2} yz + 5 x z + 6))

f ((sin (x)) 2 x - 3)

164 (3 e^{4} + 4 e^{2} + 13)

(1 + e^{t}) (- e + e^{t})

What is expand-1/324 (6-2z)^4 ?
The solution to expand-1/324 (6-2z)^4 is -4+(16z)/3-(8z^2)/3+(16z^3)/(27)-(4z^4)/(81)