What is expand (x-2)(x-2i)(x+2i) ?

The solution to expand (x-2)(x-2i)(x+2i) is x^3+4x-2x^2-8

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expand (x-2)(x-2i)(x+2i)

expand

(x - 2) (x - 2 i) (x + 2 i)

x^{3} + 4 x - 2 x^{2} - 8

Solution steps

(x - 2) (x - 2 i) (x + 2 i)

Expand

(x - 2) (x - 2 i) (x + 2 i) : (x - 2) (x^{2} + 4)

= (x - 2) (x^{2} + 4)

Apply FOIL method

(x - 2) (x^{2} + 4) : x^{3} + 4 x - 2 x^{2} - 8

= x^{3} + 4 x - 2 x^{2} - 8

(2 t^{3} L - 10 L) 2

(\frac{1}{x})^{3}

(7 - 23) (5 - 2)

- 5 ((3 z))

(18 sin (x) - 1) (18 sin (x) + 1)

What is expand (x-2)(x-2i)(x+2i) ?
The solution to expand (x-2)(x-2i)(x+2i) is x^3+4x-2x^2-8