What is expand e^{2x}(-e^{-x}+C) ?

The solution to expand e^{2x}(-e^{-x}+C) is -e^x+e^{2x}C

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expand e^{2x}(-e^{-x}+C)

expand

e^{2 x} (- e^{- x} + C)

- e^{x} + e^{2 x} C

Solution steps

e^{2 x} (- e^{- x} + C)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{2 x}, b = - e^{- x}, c = C

= e^{2 x} (- e^{- x}) + e^{2 x} C

Apply minus-plus rules

+ (- a) = - a

= - e^{2 x} e^{- x} + e^{2 x} C

e^{2 x} e^{- x} = e^{x}

= - e^{x} + e^{2 x} C

(1 + cos (3 t)) (sin (3 t))

\frac{d}{d t} ((x) (t^{3} - 2))

- \frac{1}{2} (x - 2)^{2}

\frac{d}{d t} ((x) (t + t))

(- a - x) (a + x)

What is expand e^{2x}(-e^{-x}+C) ?
The solution to expand e^{2x}(-e^{-x}+C) is -e^x+e^{2x}C