What is expand (5(2v-u^2))/(u^3v^3) ?

The solution to expand (5(2v-u^2))/(u^3v^3) is (10)/(v^2u^3)-5/(v^3u)

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expand (5(2v-u^2))/(u^3v^3)

expand

\frac{5 ( 2 v - u ^{2} )}{u ^{3} v ^{3}}

\frac{10}{v ^{2} u ^{3}} - \frac{5}{v ^{3} u}

Solution steps

\frac{5 ( 2 v - u ^{2} )}{u ^{3} v ^{3}}

Expand

5 (2 v - u^{2}) : 10 v - 5 u^{2}

= \frac{10 v - 5 u ^{2}}{v ^{3} u ^{3}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{10 v - 5 u ^{2}}{u ^{3} v ^{3}} = \frac{10 v}{u ^{3} v ^{3}} - \frac{5 u ^{2}}{u ^{3} v ^{3}}

= \frac{10 v}{v ^{3} u ^{3}} - \frac{5 u ^{2}}{v ^{3} u ^{3}}

Cancel

\frac{10 v}{u ^{3} v ^{3}} : \frac{10}{v ^{2} u ^{3}}

= \frac{10}{v ^{2} u ^{3}} - \frac{5 u ^{2}}{v ^{3} u ^{3}}

Cancel

\frac{5 u ^{2}}{u ^{3} v ^{3}} : \frac{5}{v ^{3} u}

= \frac{10}{v ^{2} u ^{3}} - \frac{5}{v ^{3} u}

(x - 1 + 32) (x - 1 - 32)

\frac{4 x + ln ( 4 x + 5 ) ( 4 x + 5 )}{4 x + 5}

\frac{1}{( x + 5 ) ( x + 7 )}

2 (2 x - \frac{2}{7} y)^{2}

What is expand (5(2v-u^2))/(u^3v^3) ?
The solution to expand (5(2v-u^2))/(u^3v^3) is (10)/(v^2u^3)-5/(v^3u)