What is 2ckx((bx-bd)/a-2b+z) ?

The solution to 2ckx((bx-bd)/a-2b+z) is (2ckx(bx-bd-2ba+za))/a

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simplify 2ckx((bx-bd)/a-2b+z)

simplify

2 c k x (\frac{b x - b d}{a} - 2 b + z)

\frac{2 c k x ( b x - b d - 2 ba + z a )}{a}

Solution steps

2 c k x (\frac{b x - b d}{a} - 2 b + z)

Join

\frac{b x - b d}{a} - 2 b + z : \frac{b x - b d - 2 ba + z a}{a}

= 2 c k x \frac{b x - b d - 2 ba + z a}{a}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 c k x ( b x - b d - 2 ba + z a )}{a}

2 (2 + 15)

- z \frac{d}{d z} (\frac{a z ( z + a )}{( z - a ) ^{3}})

\frac{( x - 1 )}{2 \cdot ( x - 3 ) ^{2}}

\frac{13 ( s + 2 ) ( s + 1 )}{s ^{3} + 9 s ^{2} + 138 s + 260}

d x (3 x - \frac{2}{x} + 1)

What is 2ckx((bx-bd)/a-2b+z) ?
The solution to 2ckx((bx-bd)/a-2b+z) is (2ckx(bx-bd-2ba+za))/a