What is expand 2(2+\times (-(6-7x))=13x-(1+4x)) ?

The solution to expand 2(2+\times (-(6-7x))=13x-(1+4x)) is 14x-8=5x-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 2(2+\times (-(6-7x))=13x-(1+4x))

expand

2 (2 + \cdot (- (6 - 7 x)) = 13 x - (1 + 4 x))

14 x - 8 = 5 x - 2

Solution steps

2 (2 + (- (6 - 7 x)) = 13 x - (1 + 4 x))

= 2 (2 + 13 = x (- (6 - 7 x)) - (1 + 4 x))

Distribute parentheses

2 \cdot 2 + 2 (- (6 - 7 x)) = 13 x + 2 (- (1 + 4 x))

Apply minus-plus rules

+ (- a) = - a

2 \cdot 2 + 2 (- (6 - 7 x)) = 13 x - 2 (1 + 4 x)

Simplify

2 \cdot 2 + 2 (- (6 - 7 x)) = 13 x - 2 (1 + 4 x) : 14 x - 8 = 5 x - 2

14 x - 8 = 5 x - 2

(\frac{x}{y} - y) (\frac{x}{y} + y)

(x - 2 - 6) \cdot (x - 2 + 6)

(26) l e f t (x^{4} - 81)

(x^{3} + 1) (2 x + \frac{2}{x ^{2}})

e^{x} sin (x) (- e^{x} sin (x) + e^{x} cos (x))

What is expand 2(2+\times (-(6-7x))=13x-(1+4x)) ?
The solution to expand 2(2+\times (-(6-7x))=13x-(1+4x)) is 14x-8=5x-2