What is (s+2+2sqrt(3)j)(s+2-2sqrt(3)j)(s+12) ?

The solution to (s+2+2sqrt(3)j)(s+2-2sqrt(3)j)(s+12) is (s^2-12j^2+4s+4)(s+12)

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simplify (s+2+2sqrt(3)j)(s+2-2sqrt(3)j)(s+12)

simplify

(s + 2 + 23 j) (s + 2 - 23 j) (s + 12)

(s^{2} - 12 j^{2} + 4 s + 4) (s + 12)

Solution steps

(s + 2 + 23 j) (s + 2 - 23 j) (s + 12)

Distribute parentheses

= (ss + s \cdot 2 + s (- 23 j) + 2 s + 2 \cdot 2 + 2 (- 23 j) + 23 j s + 23 j \cdot 2 + 23 j (- 23 j)) (s + 12)

Simplify

ss + s \cdot 2 + s (- 23 j) + 2 s + 2 \cdot 2 + 2 (- 23 j) + 23 j s + 23 j \cdot 2 + 23 j (- 23 j) : s^{2} - 12 j^{2} + 4 s + 4

= (s^{2} - 12 j^{2} + 4 s + 4) (s + 12)

(x - 5) \cdot (3 x + 6)

(10 - 2) 3 + 5

(1 + cos (t)) cos (\frac{t}{2}) + sin (t) sin (\frac{t}{2})

(5 sec (θ) + 2)^{2}

What is (s+2+2sqrt(3)j)(s+2-2sqrt(3)j)(s+12) ?
The solution to (s+2+2sqrt(3)j)(s+2-2sqrt(3)j)(s+12) is (s^2-12j^2+4s+4)(s+12)