What is expand log_{10}(3)(x+2) ?

The solution to expand log_{10}(3)(x+2) is log_{10}(3)x+2log_{10}(3)

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expand log_{10}(3)(x+2)

expand

lo g_{10} (3) (x + 2)

lo g_{10} (3) x + 2 lo g_{10} (3)

Solution steps

lo g_{10} (3) (x + 2)

Apply the distributive law:

a (b + c) = ab + a c

lo g_{10} (3) (x + 2) = lo g_{10} (3) x + lo g_{10} (3) \cdot 2

= lo g_{10} (3) x + lo g_{10} (3) \cdot 2

= lo g_{10} (3) x + 2 lo g_{10} (3)

\frac{( x - 1 ) ( x - 2 ) ( x - 3 )}{( 0 - 1 ) ( 0 - 2 ) ( 0 - 3 )}

e^{a} + e^{a} (x - a)

(1 + cos (α)) (1 + csc (α))

(a + b x + 2 c x^{2} + 3 d x^{3} + 4 e x^{4})^{2}

\frac{4 ( x + 1 )}{5 ( x + 3 )}

What is expand log_{10}(3)(x+2) ?
The solution to expand log_{10}(3)(x+2) is log_{10}(3)x+2log_{10}(3)