What is expand (2/3 a-1/3 b)^2 ?

The solution to expand (2/3 a-1/3 b)^2 is (4a^2-4ab+b^2)/9

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expand (2/3 a-1/3 b)^2

expand

(\frac{2}{3} a - \frac{1}{3} b)^{2}

\frac{4 a ^{2} - 4 ab + b ^{2}}{9}

Solution steps

(\frac{2}{3} a - \frac{1}{3} b)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(\frac{2}{3} a - \frac{1}{3} b)^{2} = (\frac{2}{3} a)^{2} - 2 \cdot \frac{2}{3} a \frac{1}{3} b + (\frac{1}{3} b)^{2}

= (\frac{2}{3} a)^{2} - 2 \cdot \frac{2}{3} a \frac{1}{3} b + (\frac{1}{3} b)^{2}

Simplify

(\frac{2}{3} a)^{2} - 2 \cdot \frac{2}{3} a \frac{1}{3} b + (\frac{1}{3} b)^{2} : \frac{4 a ^{2} - 4 ab + b ^{2}}{9}

= \frac{4 a ^{2} - 4 ab + b ^{2}}{9}

(x - \frac{1}{a}) (x - \frac{1}{b}) (x - \frac{1}{c})

\frac{( x ^{2} - 2 x + 3 ) ( 2 x + 3 )}{( x - 2 ) ( x + 5 )}

so l v e (30 - 2 h) (30 - h) (h)

(3 x) l e f t (- 118.33 x - 10 x^{2})

\frac{x ^{2} + 4}{( x ^{2} - 4 ) ^{2}}

What is expand (2/3 a-1/3 b)^2 ?
The solution to expand (2/3 a-1/3 b)^2 is (4a^2-4ab+b^2)/9