What is expand 1/((s+1)^3(s+4)) ?

The solution to expand 1/((s+1)^3(s+4)) is 1/(s^4+7s^3+15s^2+13s+4)

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expand 1/((s+1)^3(s+4))

expand

\frac{1}{( s + 1 ) ^{3} ( s + 4 )}

\frac{1}{s ^{4} + 7 s ^{3} + 15 s ^{2} + 13 s + 4}

Solution steps

\frac{1}{( s + 1 ) ^{3} ( s + 4 )}

(s + 1)^{3} = s^{3} + 3 s^{2} + 3 s + 1

= \frac{1}{( s ^{3} + 3 s ^{2} + 3 s + 1 ) ( s + 4 )}

Expand

(s^{3} + 3 s^{2} + 3 s + 1) (s + 4) : s^{4} + 7 s^{3} + 15 s^{2} + 13 s + 4

= \frac{1}{s ^{4} + 7 s ^{3} + 15 s ^{2} + 13 s + 4}

5 (2^{x} - x)^{4} (2^{x} ln (2) - 1)

\frac{- a c x ^{2} + b}{( c x ^{2} + 16 ) ^{2}}

3 (sin (t) + t cos (t))

x^{''} + 100 \cdot x \cdot (1 + 10 x^{2})

\frac{v}{( x ( x + ( a + b ) ) ( x + ( a - b ) ) )}

What is expand 1/((s+1)^3(s+4)) ?
The solution to expand 1/((s+1)^3(s+4)) is 1/(s^4+7s^3+15s^2+13s+4)