What are the solutions to the equation 2x^2-x-9=0 ?

The solutions to the equation 2x^2-x-9=0 are x=(1+sqrt(73))/4 ,x=(1-sqrt(73))/4

Find the zeros of 2x^2-x-9=0

The zeros of 2x^2-x-9=0 are x=(1+sqrt(73))/4 ,x=(1-sqrt(73))/4

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2 x^{2} - x - 9 = 0

x = \frac{1 + 73}{4}, x = \frac{1 - 73}{4}

Decimal Notation

x = 2.38600 \dots, x = - 1.88600 \dots

Solution steps

2 x^{2} - x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 9) = 73

x_{1, 2} = \frac{- ( - 1 ) \pm 73}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 73}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 73}{2 \cdot 2}

x = \frac{- ( - 1 ) + 73}{2 \cdot 2} : \frac{1 + 73}{4}

x = \frac{- ( - 1 ) - 73}{2 \cdot 2} : \frac{1 - 73}{4}

The solutions to the quadratic equation are:

x = \frac{1 + 73}{4}, x = \frac{1 - 73}{4}

6 z^{2} - 13 z + 6

z^{2} - 13 z - 30 = 0

y, 2 ∣ x ∣ + y = 7

x (x - 1) < 0

3 0^{2} + b^{2} = 8 0^{2}

What are the solutions to the equation 2x^2-x-9=0 ?
The solutions to the equation 2x^2-x-9=0 are x=(1+sqrt(73))/4 ,x=(1-sqrt(73))/4
Find the zeros of 2x^2-x-9=0
The zeros of 2x^2-x-9=0 are x=(1+sqrt(73))/4 ,x=(1-sqrt(73))/4