What is expand log_{10}(\sqrt[3]{x^2+6}) ?

The solution to expand log_{10}(\sqrt[3]{x^2+6}) is 1/3 log_{10}(x^2+6)

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expand log_{10}(\sqrt[3]{x^2+6})

expand

\frac{1}{3} lo g_{10} (x^{2} + 6)

Solution steps

Rewrite as

= lo g_{10} ((x^{2} + 6)^{\frac{1}{3}})

Apply log rule

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x),

assuming

x \geq 0

= \frac{1}{3} lo g_{10} (x^{2} + 6)

(x^{2} + 2 i)^{2} (x + 4)

sec (a) (1 - sin (a)) (sec (a) + tan (a))

(x - 2)^{2} (x - (6 i)) (x - (- 6 i))

x^{2 (a - 2)} - y^{6 b}

2 (e^{\frac{π}{2}} - 1)

What is expand log_{10}(\sqrt[3]{x^2+6}) ?
The solution to expand log_{10}(\sqrt[3]{x^2+6}) is 1/3 log_{10}(x^2+6)