What is expand s(x)9000(1-e^{-0.002x}) ?

The solution to expand s(x)9000(1-e^{-0.002x}) is 9000sx-9000e^{-0.002x}sx

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expand s(x)9000(1-e^{-0.002x})

expand

s (x) 9000 (1 - e^{- 0.002 x})

9000 s x - 9000 e^{- 0.002 x} s x

Solution steps

s (x) \cdot 9000 (1 - e^{- 0.002 x})

= 9000 s (x) (1 - e^{- 0.002 x})

Apply the distributive law:

a (b - c) = ab - a c

a = s (x) \cdot 9000, b = 1, c = e^{- 0.002 x}

= s (x) \cdot 9000 \cdot 1 - s (x) \cdot 9000 e^{- 0.002 x}

= 9000 \cdot 1 \cdot s (x) - 9000 e^{- 0.002 x} s (x)

Simplify

9000 \cdot 1 \cdot s (x) - 9000 e^{- 0.002 x} s (x) : 9000 s x - 9000 e^{- 0.002 x} s x

= 9000 s x - 9000 e^{- 0.002 x} s x

\frac{5}{4} (20 x + 12 = - 35)

n \cdot (4 n + 1 + 2 n)

(- 3 - 5) y \frac{B}{( 3.5 )}

y^{\frac{1}{3}} (y^{\frac{1}{3}} - y^{\frac{3}{5}})

(\frac{5}{3} + 9 i) l e f t (- \frac{1}{2} + 3 i)

What is expand s(x)9000(1-e^{-0.002x}) ?
The solution to expand s(x)9000(1-e^{-0.002x}) is 9000sx-9000e^{-0.002x}sx