What is (x/3+1/6)(1/6+(2y)/3) ?

The solution to (x/3+1/6)(1/6+(2y)/3) is ((2x+1)(1+4y))/(36)

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simplify (x/3+1/6)(1/6+(2y)/3)

simplify

(\frac{x}{3} + \frac{1}{6}) (\frac{1}{6} + \frac{2 y}{3})

\frac{( 2 x + 1 ) ( 1 + 4 y )}{36}

Solution steps

(\frac{x}{3} + \frac{1}{6}) (\frac{1}{6} + \frac{2 y}{3})

Simplify

\frac{x}{3} + \frac{1}{6} : \frac{2 x + 1}{6}

= \frac{2 x + 1}{6} (\frac{1}{6} + \frac{2 y}{3})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 x + 1 ) ( \frac{1}{6} + \frac{2 y}{3} )}{6}

Simplify

(2 x + 1) (\frac{1}{6} + \frac{2 y}{3}) : \frac{( 2 x + 1 ) ( 1 + 4 y )}{6}

= \frac{\frac{( 2 x + 1 ) ( 1 + 4 y )}{6}}{6}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 2 x + 1 ) ( 1 + 4 y )}{6 \cdot 6}

Multiply the numbers:

6 \cdot 6 = 36

= \frac{( 2 x + 1 ) ( 1 + 4 y )}{36}

m u lt i pl y (x^{2} + 0 x + 13) \cdot (x)

(208 x - 56) e - 4 x

\frac{( 15 p + 4 q ) ^{2}}{400}

(tan (x) + 1) (tan (x) - 7)

\frac{s ^{3} - 7 s ^{2} + 10 s + 30}{s ( s - 4 ) ( s - 3 ) ( s + 1 )}

What is (x/3+1/6)(1/6+(2y)/3) ?
The solution to (x/3+1/6)(1/6+(2y)/3) is ((2x+1)(1+4y))/(36)