What is expand derivative of sin(5x)+(4x-2)^2 ?

The solution to expand derivative of sin(5x)+(4x-2)^2 is derivative of sin(5x)+16x^2-16x+4

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expand derivative of sin(5x)+(4x-2)^2

expand

\frac{d}{d x} (sin (5 x)) + (4 x - 2)^{2}

\frac{d}{d x} (sin (5 x)) + 16 x^{2} - 16 x + 4

Solution steps

\frac{d}{d x} (sin (5 x)) + (4 x - 2)^{2}

(4 x - 2)^{2} : 16 x^{2} - 16 x + 4

= \frac{d}{d x} (sin (5 x)) + 16 x^{2} - 16 x + 4

\frac{1}{2} (t + \frac{1}{2} sin (2 t)) - v sin^{2} (t)

\frac{tan ( x )}{( x - 5 ) ( x - 3 )}

(tan (x) + 1) (tan (x) - 1)

(9 cos (x) - cos (9 x) \cdot 9)^{2}

\frac{( 4 a ^{x} + b ^{x} ) ^{2}}{4}

What is expand derivative of sin(5x)+(4x-2)^2 ?
The solution to expand derivative of sin(5x)+(4x-2)^2 is derivative of sin(5x)+16x^2-16x+4