What is expand (4xy+2x^2y)+(2x^2+3y^2)y'(x) ?

The solution to expand (4xy+2x^2y)+(2x^2+3y^2)y'(x) is 4xy+2x^2y+2x^2y'(x)+3y'(x)y^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (4xy+2x^2y)+(2x^2+3y^2)y'(x)

expand

(4 x y + 2 x^{2} y) + (2 x^{2} + 3 y^{2}) y^{'} (x)

4 x y + 2 x^{2} y + 2 x^{2} y' (x) + 3 y' (x) y^{2}

Solution steps

(4 x y + 2 x^{2} y) + (2 x^{2} + 3 y^{2}) y^{'} (x)

Expand

y^{'} (x) (2 x^{2} + 3 y^{2}) : 2 x^{2} y^{'} (x) + 3 y^{'} (x) y^{2}

= (4 x y + 2 x^{2} y) + 2 x^{2} y^{'} (x) + 3 y^{'} (x) y^{2}

Remove parentheses:

(a) = a

= 4 x y + 2 x^{2} y + 2 x^{2} y^{^{'}} (x) + 3 y^{^{'}} (x) y^{2}

x^{3} \cdot e^{3 x^{2}} (2 x + 3)

x (x^{2} + \frac{x}{4} + 4)

6 (- e^{3 x} (2 sin (2 x) - 3 cos (2 x)))

(sec (x) + tan (x))^{3} (sec (x) - tan (x))^{4}

((cos (θ) + i sin (θ)))^{3}

What is expand (4xy+2x^2y)+(2x^2+3y^2)y'(x) ?
The solution to expand (4xy+2x^2y)+(2x^2+3y^2)y'(x) is 4xy+2x^2y+2x^2y'(x)+3y'(x)y^2