What is (4x+1)(2x-2)>8x(x+5) ?

The solution to (4x+1)(2x-2)>8x(x+5) is x<-1/23

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(4x+1)(2x-2)>8x(x+5)

(4 x + 1) (2 x - 2) > 8 x (x + 5)

x < - \frac{1}{23}

Interval Notation

(- \infty, - \frac{1}{23})

Decimal Notation

x < - 0.04347 \dots

Solution steps

(4 x + 1) (2 x - 2) > 8 x (x + 5)

Rewrite in standard form

- 23 x - 1 > 0

Move

1

to the right side

- 23 x > 1

Multiply both sides by

- 1

23 x < - 1

Divide both sides by

23

x < - \frac{1}{23}

\frac{6}{5 y} + \frac{5 y}{4 x y}

- 5 x^{2} + 18 x + 8

\frac{1}{4} x + 8 \geq 12

9 x^{2} - 24 x + 16

4 x^{2} - 0.04 x + 0.0001