What is (n+1)((n(2n+1))/6+1) ?

The solution to (n+1)((n(2n+1))/6+1) is ((n+1)(6+2n^2+n))/6

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simplify (n+1)((n(2n+1))/6+1)

simplify

(n + 1) (\frac{n ( 2 n + 1 )}{6} + 1)

\frac{( n + 1 ) ( 6 + 2 n ^{2} + n )}{6}

Solution steps

(n + 1) (\frac{n ( 2 n + 1 )}{6} + 1)

Join

\frac{n ( 2 n + 1 )}{6} + 1 : \frac{6 + 2 n ^{2} + n}{6}

= (n + 1) \frac{6 + 2 n ^{2} + n}{6}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( n + 1 ) ( 6 + 2 n ^{2} + n )}{6}

\frac{10 ( 5 + 1985 )}{49}

(x^{2} - x) \cdot (x^{2} + x)

(2 x + 62 x)^{2}

\frac{d x}{( x + 3 a ) ( x + 4 a )}

(x^{2} + 1)^{2} (x^{2} - 1)

What is (n+1)((n(2n+1))/6+1) ?
The solution to (n+1)((n(2n+1))/6+1) is ((n+1)(6+2n^2+n))/6