What is expand cos(t)h(t-pi/2) ?

The solution to expand cos(t)h(t-pi/2) is thcos(t)-(pihcos(t))/2

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expand cos(t)h(t-pi/2)

expand

cos (t) h (t - \frac{π}{2})

t h cos (t) - \frac{πh cos ( t )}{2}

Solution steps

cos (t) h (t - \frac{π}{2})

= h cos (t) (t - \frac{π}{2})

Apply the distributive law:

a (b - c) = ab - a c

a = cos (t) h, b = t, c = \frac{π}{2}

= cos (t) h t - cos (t) h \frac{π}{2}

= t h cos (t) - \frac{π}{2} h cos (t)

Simplify

t h cos (t) - \frac{π}{2} h cos (t) : t h cos (t) - \frac{πh cos ( t )}{2}

= t h cos (t) - \frac{πh cos ( t )}{2}

\frac{3 ( 2 + 7 )}{3}

\frac{s + 1}{( s + 4 ) s ^{2}}

(x^{2} + (\frac{2 y}{x})) d x

(x - \frac{1}{4})^{2} + \frac{7}{2}

arctan (f (5 x^{2} + 4))

What is expand cos(t)h(t-pi/2) ?
The solution to expand cos(t)h(t-pi/2) is thcos(t)-(pihcos(t))/2