What is expand (x^2+1)y'(x)+xy-2x ?

The solution to expand (x^2+1)y'(x)+xy-2x is x^2y'(x)+y'(x)+xy-2x

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expand (x^2+1)y'(x)+xy-2x

expand

(x^{2} + 1) y^{'} (x) + x y - 2 x

x^{2} y' (x) + y' (x) + x y - 2 x

Solution steps

(x^{2} + 1) y^{'} (x) + x y - 2 x

Expand

y^{'} (x) (x^{2} + 1) : x^{2} y^{'} (x) + y^{'} (x)

= x^{2} y^{'} (x) + y^{'} (x) + x y - 2 x

(\frac{- 0.0433 - 0.0102 x}{0.0146})^{2}

(1 + \frac{1}{s}) (\frac{s}{s ^{2} + 1} + s + 1)

2 (ln (3) - 2 + \frac{2}{3})

\frac{x + 5}{( x + 1 ) ^{2} ( x + 3 )}

e^{64 + 48 k} \cdot (48 - 24 k)

What is expand (x^2+1)y'(x)+xy-2x ?
The solution to expand (x^2+1)y'(x)+xy-2x is x^2y'(x)+y'(x)+xy-2x