What is expand 2zsin(x)-2zx(1+cos(xy)) ?

The solution to expand 2zsin(x)-2zx(1+cos(xy)) is 2zsin(x)-2zx-2zxcos(xy)

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expand 2zsin(x)-2zx(1+cos(xy))

expand

2 z sin (x) - 2 z x (1 + cos (x y))

2 z sin (x) - 2 z x - 2 z x cos (x y)

Solution steps

2 z sin (x) - 2 z x (1 + cos (x y))

Apply the distributive law:

a (b + c) = ab + a c

- 2 z x (1 + cos (x y)) = - 2 z x \cdot 1 - 2 z x cos (x y)

= 2 z sin (x) - 2 z x \cdot 1 - 2 z x cos (x y)

Multiply the numbers:

2 \cdot 1 = 2

= 2 z sin (x) - 2 z x - 2 z x cos (x y)

\frac{s ^{2} + 6 s + 19}{( s + 7 ) ( s + 20 )}

\frac{x ^{2}}{2} - 2 x + (3 + 2 x) ln (x) + c

\frac{d}{d t} ((x) (sin (t) - t cos (t)))

(p + \frac{4.3}{v ^{2}}) (v - 8.9)

\frac{e ^{z}}{( z - 1 ) ^{2}}

What is expand 2zsin(x)-2zx(1+cos(xy)) ?
The solution to expand 2zsin(x)-2zx(1+cos(xy)) is 2zsin(x)-2zx-2zxcos(xy)