What is expand-e^{(-x^2-x)^2}(2x+1) ?

The solution to expand-e^{(-x^2-x)^2}(2x+1) is -2e^{x^4+2x^3+x^2}x-e^{x^4+2x^3+x^2}

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expand-e^{(-x^2-x)^2}(2x+1)

expand

- e^{(- x^{2} - x)^{2}} (2 x + 1)

- 2 e^{x^{4} + 2 x^{3} + x^{2}} x - e^{x^{4} + 2 x^{3} + x^{2}}

Solution steps

- e^{(- x^{2} - x)^{2}} (2 x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = - e^{(- x^{2} - x)^{2}}, b = 2 x, c = 1

= - e^{(- x^{2} - x)^{2}} \cdot 2 x + (- e^{(- x^{2} - x)^{2}}) \cdot 1

Apply minus-plus rules

+ (- a) = - a

= - 2 e^{(- x^{2} - x)^{2}} x - 1 \cdot e^{(- x^{2} - x)^{2}}

Simplify

- 2 e^{(- x^{2} - x)^{2}} x - 1 \cdot e^{(- x^{2} - x)^{2}} : - 2 e^{x^{4} + 2 x^{3} + x^{2}} x - e^{x^{4} + 2 x^{3} + x^{2}}

= - 2 e^{x^{4} + 2 x^{3} + x^{2}} x - e^{x^{4} + 2 x^{3} + x^{2}}

e n^{l n (x)} (2 x + 2)

\frac{( x + Δ x ) ^{2} ( x ^{2} y + 3 y ^{3} )}{Δ x}

(365, 8 - \frac{135000}{41} i) \cdot (0.6222 + 0.13334 i)

\frac{4 ( q - p )}{3 ( q + p )}

\frac{( 2 x + 3 ) ^{2}}{( 4 x - 1 ) ^{3}}

What is expand-e^{(-x^2-x)^2}(2x+1) ?
The solution to expand-e^{(-x^2-x)^2}(2x+1) is -2e^{x^4+2x^3+x^2}x-e^{x^4+2x^3+x^2}