What is expand (b(4h-3y)(-3y+h))/(18h) ?

The solution to expand (b(4h-3y)(-3y+h))/(18h) is (by^2}{2h}-\frac{5by)/6+(2bh)/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (b(4h-3y)(-3y+h))/(18h)

expand

\frac{b ( 4 h - 3 y ) ( - 3 y + h )}{18 h}

\frac{b y ^{2}}{2 h} - \frac{5 b y}{6} + \frac{2 bh}{9}

Solution steps

\frac{b ( 4 h - 3 y ) ( - 3 y + h )}{18 h}

Expand

b (4 h - 3 y) (- 3 y + h) : 9 b y^{2} - 15 bh y + 4 b h^{2}

= \frac{9 b y ^{2} - 15 bh y + 4 b h ^{2}}{18 h}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 b y ^{2} - 15 bh y + 4 b h ^{2}}{18 h} = \frac{9 b y ^{2}}{18 h} - \frac{15 bh y}{18 h} + \frac{4 b h ^{2}}{18 h}

= \frac{9 b y ^{2}}{18 h} - \frac{15 bh y}{18 h} + \frac{4 b h ^{2}}{18 h}

Cancel

\frac{9 b y ^{2}}{18 h} : \frac{b y ^{2}}{2 h}

= \frac{b y ^{2}}{2 h} - \frac{15 bh y}{18 h} + \frac{4 b h ^{2}}{18 h}

Cancel

\frac{15 bh y}{18 h} : \frac{5 b y}{6}

= \frac{b y ^{2}}{2 h} - \frac{5 b y}{6} + \frac{4 b h ^{2}}{18 h}

Cancel

\frac{4 b h ^{2}}{18 h} : \frac{2 bh}{9}

= \frac{b y ^{2}}{2 h} - \frac{5 b y}{6} + \frac{2 bh}{9}

(x + 3 - 2) \cdot (x + 3 + 2)

\frac{3 k + 2 l ^{2}}{l}

(- a - a^{2} - 4)^{2}

(x^{2} + \frac{1}{25 x ^{2}}) \cdot 5

\frac{x ( 16 - x ) ^{2}}{64}

What is expand (b(4h-3y)(-3y+h))/(18h) ?
The solution to expand (b(4h-3y)(-3y+h))/(18h) is (by^2}{2h}-\frac{5by)/6+(2bh)/9