What is (1/(s-2)+1)(s-3) ?

The solution to (1/(s-2)+1)(s-3) is ((s-1)(s-3))/(s-2)

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simplify (1/(s-2)+1)(s-3)

simplify

(\frac{1}{s - 2} + 1) (s - 3)

\frac{( s - 1 ) ( s - 3 )}{s - 2}

Solution steps

(\frac{1}{s - 2} + 1) (s - 3)

Join

\frac{1}{s - 2} + 1 : \frac{s - 1}{s - 2}

= \frac{s - 1}{s - 2} (s - 3)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( s - 1 ) ( s - 3 )}{s - 2}

\frac{- x ^{2} - 2}{( x ^{2} + x - 2 ) ^{2}}

(20 b d z + 32 c g a) + k (20 b d z + 32 c g a)

(\frac{b}{a} (x - z) + y - c)^{2}

2 (e - 1) + \frac{e ^{6} + e ^{2} - 2}{4 e ^{2}}

\frac{1}{t ^{2}} (1 + e^{2 t} - 2 e^{t})

What is (1/(s-2)+1)(s-3) ?
The solution to (1/(s-2)+1)(s-3) is ((s-1)(s-3))/(s-2)