What is expand ((t+1)^2)/(3(2t^2-1)^3) ?

The solution to expand ((t+1)^2)/(3(2t^2-1)^3) is (t^2+2t+1)/(24t^6-36t^4+18t^2-3)

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expand ((t+1)^2)/(3(2t^2-1)^3)

expand

\frac{( t + 1 ) ^{2}}{3 ( 2 t ^{2} - 1 ) ^{3}}

\frac{t ^{2} + 2 t + 1}{24 t ^{6} - 36 t ^{4} + 18 t ^{2} - 3}

Solution steps

\frac{( t + 1 ) ^{2}}{3 ( 2 t ^{2} - 1 ) ^{3}}

(2 t^{2} - 1)^{3} = 8 t^{6} - 12 t^{4} + 6 t^{2} - 1

= \frac{( t + 1 ) ^{2}}{3 ( 8 t ^{6} - 12 t ^{4} + 6 t ^{2} - 1 )}

(t + 1)^{2} = t^{2} + 2 t + 1

= \frac{t ^{2} + 2 t + 1}{3 ( 8 t ^{6} - 12 t ^{4} + 6 t ^{2} - 1 )}

Expand

3 (8 t^{6} - 12 t^{4} + 6 t^{2} - 1) : 24 t^{6} - 36 t^{4} + 18 t^{2} - 3

= \frac{t ^{2} + 2 t + 1}{24 t ^{6} - 36 t ^{4} + 18 t ^{2} - 3}

\frac{( ( x + h ) ^{2} - 5 ) - ( x ^{2} - 5 )}{h}

\frac{8 n}{( n + 4 ) ( n + 5 )}

\frac{- 5 ^{3} \cdot 2 ^{8}}{1 0 ^{6}}

(\frac{4}{5} x - \frac{3}{5} y) 60

e^{c} (c^{2} - 2)

What is expand ((t+1)^2)/(3(2t^2-1)^3) ?
The solution to expand ((t+1)^2)/(3(2t^2-1)^3) is (t^2+2t+1)/(24t^6-36t^4+18t^2-3)