What is expand log_{10}(2)((2x+1)/(x-5)) ?

The solution to expand log_{10}(2)((2x+1)/(x-5)) is (2log_{10}(2)x+log_{10}(2))/(x-5)

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expand log_{10}(2)((2x+1)/(x-5))

expand

lo g_{10} (2) (\frac{2 x + 1}{x - 5})

\frac{2 lo g _{10} ( 2 ) x + lo g _{10} ( 2 )}{x - 5}

Solution steps

lo g_{10} (2) (\frac{2 x + 1}{x - 5})

Remove parentheses:

(a) = a

= lo g_{10} (2) \frac{2 x + 1}{x - 5}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 x + 1 ) lo g _{10} ( 2 )}{x - 5}

Expand

(2 x + 1) lo g_{10} (2) : 2 lo g_{10} (2) x + lo g_{10} (2)

= \frac{2 lo g _{10} ( 2 ) x + lo g _{10} ( 2 )}{x - 5}

2 (x^{2} - 7 x + 7)^{2}

\frac{2 x - 3}{5}

- 1.5 (5 x + 2 y = - 9)

(4 a^{2} + 3 a + 6)^{7}

\frac{3 y ^{2} - 1 - 2 y}{2 ( - 1 + x )}

What is expand log_{10}(2)((2x+1)/(x-5)) ?
The solution to expand log_{10}(2)((2x+1)/(x-5)) is (2log_{10}(2)x+log_{10}(2))/(x-5)