What is expand pi(7x-(8x^9)/9-(2x^{17})/(17)) ?

The solution to expand pi(7x-(8x^9)/9-(2x^{17})/(17)) is -(2pix^{17}}{17}-\frac{8pix^9)/9+7pix

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expand pi(7x-(8x^9)/9-(2x^{17})/(17))

expand

π (7 x - \frac{8 x ^{9}}{9} - \frac{2 x ^{17}}{17})

- \frac{2 π x ^{17}}{17} - \frac{8 π x ^{9}}{9} + 7 π x

Solution steps

π (7 x - \frac{8 x ^{9}}{9} - \frac{2 x ^{17}}{17})

Distribute parentheses

= π 7 x + π (- \frac{8 x ^{9}}{9}) + π (- \frac{2 x ^{17}}{17})

Apply minus-plus rules

+ (- a) = - a

= 7 π x - π \frac{8 x ^{9}}{9} - π \frac{2 x ^{17}}{17}

Simplify

7 π x - π \frac{8 x ^{9}}{9} - π \frac{2 x ^{17}}{17} : - \frac{2 π x ^{17}}{17} - \frac{8 π x ^{9}}{9} + 7 π x

= - \frac{2 π x ^{17}}{17} - \frac{8 π x ^{9}}{9} + 7 π x

(\frac{4}{5}) (3^{n}) (1 + 5 x)

\frac{7 e ^{16}}{2 ( s + 4 )} - \frac{3 e ^{8}}{2 ( s + 2 )}

(\frac{1}{2} x + 1)^{2}

(x (4 y d x + 2 x d y) + y^{3} (3 y x + 5 x d y)) (x^{2} y^{3})

s cos (x) (1 + t a gx)

What is expand pi(7x-(8x^9)/9-(2x^{17})/(17)) ?
The solution to expand pi(7x-(8x^9)/9-(2x^{17})/(17)) is -(2pix^{17}}{17}-\frac{8pix^9)/9+7pix